x/3^2x=27

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Solution for x/3^2x=27 equation:



x/3^2x=27
We move all terms to the left:
x/3^2x-(27)=0
Domain of the equation: 3^2x!=0
x!=0/1
x!=0
x∈R
We multiply all the terms by the denominator
x-27*3^2x=0
Wy multiply elements
-81x^2+x=0
a = -81; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-81)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-81}=\frac{-2}{-162} =1/81 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-81}=\frac{0}{-162} =0 $

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